Thomas Archer - English divine. Article “Thomas Archer (divine)” in English Wikipedia has 20.1 points for quality (as of July 1, 2025). The article contains 4 references and 3 sections.
Since the creation of article “Thomas Archer (divine)”, its content was written by 20 registered users of English Wikipedia and edited by 20 registered Wikipedia users in all languages.
The article is cited 1 times in English Wikipedia and cited 1 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | English: #1826513 10.2017 |
Global: #3275944 10.2017 |
| Best Rank | English: #328719 01.2022 |
Global: #877088 01.2022 |
On 15 February 2026 in multilingual Wikipedia, Internet users most often read articles on the following topics: Jeffrey Epstein, Wuthering Heights, 2026 Winter Olympics, Epstein files, Ilia Malinin, Wuthering Heights, Ghislaine Maxwell, Lucas Pinheiro Braathen, 2026 Winter Olympics medal table, Valentine's Day.
In English Wikipedia the most popular articles on that day were: Jeffrey Epstein, Wuthering Heights, Wuthering Heights (2026 film), 2026 Winter Olympics, Lucas Pinheiro Braathen, Ice hockey at the 2026 Winter Olympics – Men's tournament, Epstein files, John F. Kennedy Jr., Anthony Kim, James Van Der Beek.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(4.69+3.25+0+21.43+71.3)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
